[SSL Observatory] Number of CAs

[Chris Palmer]

On Wed, Dec 7, 2011 at 12:43 PM, Phillip Hallam-Baker <hallam at gmail.com> wrote:

> The problem that comes up is that if CA X has created an intermediary for an
> external organization it is going to be for a customer. That customer
> relationship is going to be governed by a contract and the terms of that
> agreement may not have anticipated revealing the information at issue.

So CAs sell public signing power to private organizations. So the
Observatory has surely *under*counted, right?

> The methodology does not result in a
> figure of 650, it results in a number of 50-650 or as we would say in
> physics, 350+/-300.

Why do you think it could be as low as 50? What is your methodology?


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